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Get QuoteÁlgebra. Hallar la excentricidad (x^2)/100+ (y^2)/64=1. x2 100 + y2 64 = 1 x 2 100 + y 2 64 = 1. Simplifique cada término de la ecuación para poder igualar el lado derecho de la misma a 1 1. La forma estándar de una elipse o hipérbola requiere igualar el lado derecho de la ecuación a 1 1. x2 100 + y2 64 = 1 x 2 100 + y 2 64 = 1.
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Get QuoteEscribe todos los números enteros que cumplen la condición dada en cada caso. a. -2≤x≤3 -5 < x < -1 2≤x≤6 -6 ≤ x < 0 d. 4< x≤9 b. e. ; … C. f.. -8≤ x ≤ 8 porfa Ayudennn porfa, doy algo que no es corona Escribí fracciones equivalentes a …
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Get Quotelim x (√ (x^2+100)+x)∞limx/ (√ (x^2+100)+x),x→-∞-x,-1;x→+∞x,1. 1. 5. . . Lim (1-3/2n)^4n+5.n,. 1. lim { (2+3x)/ (3+3x)}x,x,, …
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Get QuoteExplicación paso a paso: primero veamos si el limite es indeterminado, esto es. luego el limite es indeterminado. Ahora procedamos a eliminar la indeterminación. perdón la fui insertar aquí debajo, pero no me di cuenta que estaba el pulsor arriba de la explicación. A acobdarfq y otros 12 usuarios les ha parecido útil esta respuesta.
Get Quote5x2=10 Two solutions were found : x = ± √2 = ± 1.4142 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... More Items. Share. Copy. Copied to clipboard. x^{2}-100=0 . Subtract 100 from both sides. left(x-10right)left(x+10right)=0 ...
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Get QuoteWe will make our imaginary number (i) equal to -1. The sum of squares formula we will use to factor x^2+100 with our imaginary number is as follows: a 2 + b 2 = (a + bi) • (a − bi) We start by setting up our problem in mathematical terms like this: x 2 + 100. As you can see, our problem does not look like the left side of the formula, so ...
Get QuoteSolution 2 . One ... Solution 1 . One may write, for x = 1, x−1x2−1. (x+ 1) = 1+1 = 2. Solution 2 . One ... Calculate limit for, limlimits_ {xto 0}frac {1-cos (x^6)} {x^ {12}}, but in there have suprize., but in there have suprize.
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Get QuoteAnswer (1 of 7): Can you show two methods of factoring 4x^2 - 100 ? 4x^2 - 100 4*(- 100) = - 400 = - 20 * 20 AND - 20 + 20 = 0 4x^2 - 20x + 20x - 100 4x(x - 5) + 20(x - 5) (4x + 20)(x - 5) 4(x + 5)(x - 5) This is called the AC method of factoring. 4x^2 - 100 4*(x^2 - 25) 4*(x + 5)(x - ...
Get QuoteFactor x^2-100. x2 − 100 x 2 - 100. Rewrite 100 100 as 102 10 2. x2 − 102 x 2 - 10 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = ( a + b) ( a - b) where a = x a = x and b = 10 b = 10. (x+10)(x −10) ( x + 10) ( x - 10)
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